$\sqrt{\frac{1}{3}} = \frac{1}{3} \sqrt{3}$ en ook $\sqrt{\frac{1}{2}} = \frac{1}{2} \sqrt{2}$

$\sqrt{\frac{1}{3}} = \sqrt{\frac{3}{9}} = \sqrt{\frac{1}{9}} \cdot \sqrt{3} = \frac{1}{3} \sqrt{3}$

Ze zijn elkaars omgekeerde, want $\sqrt{\frac{1}{n} \cdot} \sqrt{n} = \sqrt{\frac{1}{n} \cdot n} = \sqrt{1} = 1$

$\frac{1}{7} \sqrt{14}$

$\frac{1}{10} \sqrt{30}$

$\frac{1}{4} \sqrt{2}$

$\sqrt{\frac{1}{2}} = \frac{1}{2} \sqrt{2}$ , $\sqrt{4 \frac{1}{2}} = \sqrt{\frac{9}{2}} = \frac{3}{2} \sqrt{2}$ , $\sqrt{12 \frac{1}{2}} = \sqrt{\frac{25}{2}} = \frac{5}{2} \sqrt{2}$ en $\sqrt{24 \frac{1}{2}} = \sqrt{\frac{49}{2}} = \frac{7}{2} \sqrt{2}$ , dus
$\frac{1}{2} \sqrt{2} + \frac{3}{2} \sqrt{2} + \frac{5}{2} \sqrt{2} + \frac{7}{2} \sqrt{2} = \frac{16}{2} \sqrt{2} = 8 \sqrt{2}$ .

$3 \sqrt{3}$	$6$
$9 \sqrt{2}$	$40$
$6 \sqrt{5}$	$40$
kan niet eenvoudiger	$2 \sqrt{5}$

$1 \frac{1}{3} \sqrt{6}$

$2$

$12$

$1$

$2 \sqrt{\frac{2}{3}} = \sqrt{4} \cdot \sqrt{\frac{2}{3}} = \sqrt{\frac{8}{3}} = \sqrt{2 \frac{2}{3}}$

$3 \sqrt{\frac{3}{8}} = \sqrt{9} \cdot \sqrt{\frac{3}{8}} = \sqrt{\frac{27}{8}} = \sqrt{3 \frac{3}{8}}$

$\sqrt{\sqrt{5} + 1} \cdot \sqrt{\sqrt{5} - 1} = \sqrt{5 - 1} = 2$

$2$ , $4$ , $2$

$4$	$2$
$10$	$\frac{1}{100}$

$10 \sqrt{10}$	$2 \sqrt{2}$
$20$	$10$
$100$	$2$

$8 \sqrt{6}$	$4 \sqrt{3}$
$2 \sqrt{6}$	$0$
$90$	$12$
$1 \frac{2}{3}$	$1$

$5 \sqrt{5}$	$5 \sqrt{11}$
$\sqrt{5}$	$\sqrt{11}$
$30$	$66$
$1 \frac{1}{2}$	$1 \frac{1}{2}$

$\sqrt{3}$	$\frac{1}{2} \sqrt{2}$	$\sqrt{7}$
$2$	$\frac{1}{2}$	$\frac{1}{2} \sqrt{2}$

$2 \frac{1}{2} \sqrt{2}$	$\frac{1}{5} \sqrt{15}$
$2 \frac{1}{3} \sqrt{6}$	$6$
$2 \frac{1}{7} \sqrt{14}$	$0,2$
$100$	$2$